Question

For a spontaneous reaction the $\Delta G$, equilibrium constant $\left(K_{eq}\right)$ and $E_{cell}^0$ will be respectively

• A. -ve , >1 , -ve
• B. -ve , <1 , -ve
• C. +ve , >1 , -ve
• D. -ve , >1 , +ve

Answer 1

The correct option is D -ve , >1 , +ve

$\Delta G^o=-RTlnKeq$
$\Delta G^o=$ will be negative for spontaneous process
$Keqm>1$for spontaneous process
$E^{o}cell>O$ for spontaneous process
$nF{E}_{cell}^o=RTlnKeq$
$\therefore E_{cell}^o>o$