For a spring mass system, its potential energy at any position is

\frac{1}{2} m ω^{2} x^{2}

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\frac{1}{4} m ω^{2} (A^{2} - x^{2})

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\frac{1}{8} m ω^{2} A^{2}

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\frac{1}{6} m ω^{2} (x^{2} - A^{2})

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Solution

The correct option is A $\frac{1}{2} m ω^{2} x^{2}$
When suspended it is at an extreme
Assuming A to be the amplitude
Potential energy
$= \frac{1}{2} m ω^{2} A^{2}$

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