Question

For a symmetrical frequency distribution, we have:
(a) mean < mode < median
(b) mean > mode > median
(c) mean = mode = median
(d) mode = $\frac{1}{2}$ (mean + median)

Answer 1

$\left(c\right)\mathrm{mean}=\mathrm{mode}=\mathrm{median}$
A symmetric distribution is one where the left and right hand sides of the distribution are roughly equally balanced around the mean.