MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Course of The First World War - Eastern War Front

For a symmetr...

Question

For a symmetrical three-hinged arch of span 12 m and rise 2m, if the influence line diagram for horizontal thrust at either support is to be drawn, then the maximum value of influence line ordinate is_____.

Open in App

Solution

\(\dfrac{l}{4h}=\dfrac{12}{4\times 2}=1.5\)

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion (A): In a parabolic symmetrical three-hinged arch the bending moment at any section due to dead load is zero.

Reason(R): In influence line diagram for moment at a section of an arch, the simply supported moment diagram and

^{'} H_{x y^{'}}

diagram have equal areas.

Q. A three-hinged parabolic arch of span 'l' and rise 'h' is subjected to a u.d.l. of intensity 'w'. Then the horizontal thrust at the supports is

Q. A three-hinged arch of span L and rise R is subjected to a concentrated load P at the crown-point. The horizontal thrust at the support is

Q. The maximum horizontal thrust developed in a symmetrical two hinged parabolic arch having span. 30 m and central rise 6 m due to a moving 100 kN load will be _______ kN.

Q. Which of the following statements is/are correct?

1. For statically determinate structures. magnitudes for maximum effects due to a series of concentrated loads can be established with the aid of influence lines.

2. Cables in suspension bridges will not take the parabolic shape if uniformly loaded along the horizontal span.

3. In a three-hinged arch structure, the normal force, shear and moment at any section are not influenced by the horizontal reaction at the support.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Course of The First World War - Eastern War Front

HISTORY

Watch in App

explore_more_icon

Explore more

Course of The First World War - Eastern War Front

Standard X History

Join BYJU'S Learning Program

CrossIcon