For a system having transfer function G(s)=−s+1s+1, a unit step input is applied at time t=0. The value of the response of the system of t=1.5 sec(rounded off to three decimal places ) is .
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Solution
G(s)=−s+1s+1
System output, Y(s)=G(s).1s=−s+1s+1.1s =1s−2s+1 y(t)=u(t)−2e−tu(t) y(1.5)=1−2e−1.5 =1−0.446=0.554