1
Question
For a theromdynamic process ΔQ=−50 cal and ΔW=−20 cal. If the initial internal energy is −30 cal then, final internal energy will be
For a theromdynamic process ΔQ=−50 cal and ΔW=−20 cal. If the initial internal energy is −30 cal then, final internal energy will be
Open in App
Solution
The correct option is D −60 cal
Using the first law, we know that ΔQ−ΔW=ΔU
Thus −50−(−20)=Uf−Ui
or, Uf=−30−30=−60 cal
Using the first law, we know that ΔQ−ΔW=ΔU
Thus −50−(−20)=Uf−Ui
or, Uf=−30−30=−60 cal
Suggest Corrections
0
Similar questions
