Question

For a transistor, ${\alpha }_{dc}$ and ${\beta }_{dc}$ are the current ratios, then the value of $\frac{{\beta }_{dc}-{\alpha }_{dc}}{{\alpha }_{dc}\cdot {\beta }_{dc}}$ is

• A. $1$
• B. $1.5$
• C. $2$
• D. $2.5$

Answer 1

The correct option is A $1$

$\frac{{\beta }_{dc}-{\alpha }_{dc}}{{\alpha }_{dc}.{\beta }_{dc}}$

$=\frac{\frac{\alpha }{1-\alpha }-\alpha }{\frac{\alpha }{1-\alpha }.\alpha }$

$=\frac{\alpha -\alpha (1-2)}{{\alpha }^2}$

$=\frac{{\alpha }^2}{{\alpha }^2}$

$=1$