Question

For a transistor amplifier in common emitter configuration for load impedance of (1 k $\Omega$ - = 25) the current gain is ________________.

• A. -5.2
• B. 15.7
• C. -24.8
• D. -48.48

Answer 1

The correct option is D -48.48

In common emitter configuration current gain

$A_i=\frac{-h_{fe}}{1+h_{oe}{R}_L}=\frac{-50}{1+25\times {10}^{-6}\times {10}^3}=-48.78$