For a transistor, the current amplification factor is $0.8$ . The transistor is connected in common base configuration, the change in collector current when the base current changes by $6 m A$ is

6 m A

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4.8 m A

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24 m A

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8 m A

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Solution

The correct option is B $24 m A$
Given that: $α = 0.8$
$I_{b} = 6 m A$
Now, $β = \frac{α}{1 - α}$

$β = \frac{0.8}{1 - 0.8}$
$β = \frac{0.8}{0.2} = 4$
Since, $β = \frac{I_{c}}{I_{b}}$
$\Rightarrow I_{c} = β I_{b}$
$∴ I_{c} = (4) (6) = 24 m A$

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For a transistor, the current amplification factor is 0.8. The transistor is connected in common base configuration, the change in collector current when the base current changes by 6 mA is

The correct option is B 24 mAGiven that: α=0.8Ib=6 mANow, β=α1−αβ=0.81−0.8β=0.80.2=4Since, β=IcIb⇒Ic=βIb∴Ic=(4)(6)=24 mA

For a transistor, the current amplification factor is $0.8$ . The transistor is connected in common base configuration, the change in collector current when the base current changes by $6 m A$ is

The correct option is B $24 m A$
Given that: $α = 0.8$
$I_{b} = 6 m A$
Now, $β = \frac{α}{1 - α}$

$β = \frac{0.8}{1 - 0.8}$
$β = \frac{0.8}{0.2} = 4$
Since, $β = \frac{I_{c}}{I_{b}}$
$\Rightarrow I_{c} = β I_{b}$
$∴ I_{c} = (4) (6) = 24 m A$