For a travelling wave represented by equation- y-0-2sin 2- x-110t-12 SI units-The phase difference between particles at x1-4-5 m and x2-7 m is

We know that, Δϕ = 2πλΔ x Given, nbsp; nbsp;y=0.2sin 2π ( x 110t+12 ) on comparing with general equation, we get nbsp; k= 2πλ=2π So, Δϕ =2π (Δ x)=2π (7 4. ...

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Standard XI

Physics

Sinusoidal Wave

For a travell...

Question

For a travelling wave represented by equation, $y = 0.2 sin 2 π (x - 110 t + \frac{1}{2})$ (SI units).
The phase difference between particles at $x_{1} = 4.5 m$ and $x_{2} = 7 m$ is

π

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3 π

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5 π

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7 π

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Solution

The correct option is C $5 π$
We know that, $Δ ϕ = \frac{2 π}{λ} Δ x$
Given, $y = 0.2 sin 2 π (x - 110 t + \frac{1}{2})$
on comparing with general equation, we get
$k = \frac{2 π}{λ} = 2 π$
So,
$Δ ϕ = 2 π (Δ x) = 2 π (7 - 4.5) = 5 π$

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Sinusoidal Wave

Standard XI Physics

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For a travelling wave represented by equation, y=0.2sin2π(x−110t+12) (SI units). The phase difference between particles at x1=4.5 m and x2=7 m is

The correct option is C 5πWe know that, Δϕ=2πλΔx Given, y=0.2sin2π(x−110t+12) on comparing with general equation, we get k=2πλ=2π So, Δϕ=2π(Δx)=2π(7−4.5)=5π

For a travelling wave represented by equation, $y = 0.2 sin 2 π (x - 110 t + \frac{1}{2})$ (SI units).
The phase difference between particles at $x_{1} = 4.5 m$ and $x_{2} = 7 m$ is

The correct option is C $5 π$
We know that, $Δ ϕ = \frac{2 π}{λ} Δ x$
Given, $y = 0.2 sin 2 π (x - 110 t + \frac{1}{2})$
on comparing with general equation, we get
$k = \frac{2 π}{λ} = 2 π$
So,
$Δ ϕ = 2 π (Δ x) = 2 π (7 - 4.5) = 5 π$