For a two digit number, the digit at tens place is twice the digit at the units place. If 36 be subtracted from the number, the digits of the number get reversed. Find the number.

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Solution

The correct option is D 84
Let $a$ be the digit at unit place. Then digit at tens place is $‘ 2 a^{'}$ .
Then,
Given number $= (2 a) \times 10 + a = 21 a$

For number with reversed digit,
$‘ a^{'}$ will be at tens place and $‘ 2 a^{'}$ will be at unit place.

Number with reversed digit $= a \times 10 + 2 a = 12 a$

From given condition, we get,
$21 a - 36 = 12 a$
$21 a - 12 a = 36$
$9 a = 36$
$a = 4$

Hence, the given number is $“ 21 a ”$ i.e. $21 \times 4 = 84$

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