For a uniformly accelerated motion, the average acceleration is equal to

unity

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negative

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zero

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uniform acceleration

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Solution

The correct option is C uniform acceleration
Average acceleration is :
$a_{a v e r a g e} = \frac{v_{f i n a l} - v_{i n i t i a l}}{t_{t o t a l}}$

$v_{f i n a l} = v_{i n i t i a l} + a t$
$v_{f i n a l} - v_{i n i t i a l} = a t$

By putting that value in first equation we will get :
$a_{a v e r a g e} = a$

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