Question

For acid catalysed hydrolysis of ester rate law obtained is rate $=\left[ester\right]\left[H^{+}\right],$
where $k=0.01M^{-1}{hr}^{-1}.$ What is the half-life if the initial concentrations are $0.02M$ for the ester and $0.05M$ for the catalyzing acid?

• A. $1429$ hours
• B. $5000$ hours
• C. $1386$ hours
• D. $2$ hours

Answer 1

The correct option is B $5000$ hours

it is an example of psevdo first order reaction.

$\therefore t_{1/2}=\frac{1}{K\left[ester\right]}$

$=\frac{1}{0.01\times 0.02}$

$=5000$ hours