Question

For adiabatic expansion of a monoatomic perfect gas, the volume increases by 24%. The percentage of decrease in pressure is

• A. 24%
• B. 40%
• C. 48%
• D. 71%

Answer 1

Answer: (B)

40%

For a monoatomic gas, $\gamma =1.33$
Now, for an adiabatic process, $P{V}^{\gamma }=constant$
Now, if V be the initial volume, new volume = 1.24 V

Substituting these values in the above expression,
if P be the initial volume, final volume comes out to be approximately, 0.6P
Thus the pressure has decreased by 40%