Question

For adsorption of a gas on a solid, the plot of $log\frac{x}{m}$ Vs log p would be

• A. Linear with slope log K
• B. Linear with slope $\frac{1}{n}$
• C. Parabola with slope $\frac{1}{n}$
• D. Hyperbola with slope log K

Answer 1

The correct option is B Linear with slope $\frac{1}{n}$

$\frac{x}{m}=k{p}^{\frac{1}{n}}=log\frac{x}{m}=logk+\frac{1}{n}logp$