For all a, b ∈R the function f(x)=3x4−4x3+6x2+ax+b has
A
no extremum
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B
exactly one extremum
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C
exactly two extremum
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D
three extremum
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Solution
The correct option is B exactly one extremum f(x)=3x4−4x3+6x2+ax+b f′(x)=g(x)=12x3−12x2+12x+a f"(x)=36x2−24x+12=12(3x2−2x+1) Clearly f"(x)>0 f′(x) is increasing and it is cubic polynomial therefore it have at most one real root. ⇒f′(x)=0 at exactly one point. ⇒ The given function has exactly one extremum.