For all complex numbers z1,z2 satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is
A
0
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B
2
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C
7
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D
17
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Solution
The correct option is C2 Ans.(b). The two circles are C1(0,0), r1=12 C2(3,4), r2=5 and it passes through origin, the center of C1. C1C2=5<r1−r2=7 Hence circle C2 lies inside circle C1. Therefore minimum distance between them is AB=C1B−C1A−r1−2r2=12−10=2