CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

For all complex numbers z1,z2, satisfying |z1|=12 and |z2−3−4i|=5, the minimum value of |z1−z2| is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
17
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 2
C1(0,0) is center of bigger circle and C2(3,4) is center of smaller circle
C1B=r1=12 (radius of bigger circle)
C2A=r2=5 (radius of smaller circle)
C1C2=5, minimum value of |z1z2|=AB
now, C1C2+C2A+AB=C1BAB=1255=2

396896_263168_ans.PNG

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Representation and Trigonometric Form
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon