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Question

For all nN, 72n48n1 is divisible by

A
2304
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B
576
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C
24
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D
18
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Solution

The correct options are
A 2304
B 576
C 24
D 18
a=72n48n1=148n+(1+48)n
a=148n+(1+nC148+nC2482+...+nCn48n)=482(nC2+nC348+...+nCn48n2)
a=2304(nC2+nC348+...+nCn48n2)
Therefore, a is divisible by 2304.
Ans: A

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