Question

For all numbers $x$ and $y$, let $x△y$ be defined as $x△y=x^2+xy+y^2$. What is the value of $\left(3△1\right)△1$?

• A. 5
• B. 13
• C. 27
• D. 170
• E. 183

Answer 1

The correct option is E 183

$\left(3\Delta 1\right)\Delta 1=(3^2+3\ast 1+1^2)\Delta 1$

$=(9+3+1)\Delta 1$

$=\left(13\Delta 1\right)$

$=({13}^2+13\times 1+1^2)$

$=183$