For all positive integers a and b- if a- b- let a- b be defined as a - ba - b- What is the value of 1-011 - 11-

The correct option is B 1.022 Given, a b= a+b a b for a≠ b and a,b are positive integers. 1011 11= 1011+11 1011 11 = 1022 1000 ...

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Standard XII

Chemistry

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For all posit...

Question

For all positive integers a and b, if $a \neq b$ , let $a ◊ b$ be defined as $\frac{a + b}{a - b}$ . What is the value of $1, 011 ◊ 11$ ?

1.011

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1.022

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1.121

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2.111

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10.220

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Solution

The correct option is B $1.022$
Given, $a ♢ b = \frac{a + b}{a - b}$ for $a \neq b$ and $a, b$ are positive integers.

$1011 ♢ 11 = \frac{1011 + 11}{1011 - 11} = \frac{1022}{1000} = 1.022$

So, the correct option is $B$ .

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For all positive integers a and b, if a≠b, let a◊b be defined as a+ba−b. What is the value of 1,011◊11?

The correct option is B 1.022Given, a♢b=a+ba−b for a≠b and a,b are positive integers.1011♢11=1011+111011−11=10221000=1.022So, the correct option is B.

For all positive integers a and b, if $a \neq b$ , let $a ◊ b$ be defined as $\frac{a + b}{a - b}$ . What is the value of $1, 011 ◊ 11$ ?

The correct option is B $1.022$
Given, $a ♢ b = \frac{a + b}{a - b}$ for $a \neq b$ and $a, b$ are positive integers.

$1011 ♢ 11 = \frac{1011 + 11}{1011 - 11} = \frac{1022}{1000} = 1.022$

So, the correct option is $B$ .