For all positive integral values of n, $3^{2 n} - 2 n + 1$ is divisible by

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Solution

The correct option is A 2
Putting $n = 2 i n 3^{2 n} - 2 n + 1$ then,
$3^{2 \times 2} - 2 \times 2 + 1 = 81 - 4 + 1 = 78$ which is divisible by 2.

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