For all real permissible values of m, if the straight lines y=mx±√9m2−4 are tangents to a hyperbola, then equation of the hyperbola is
A
9x2−4y2=64
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B
4x2−9y2=64
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C
9x2−4y2=36
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D
4x2−9y2=36
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Solution
The correct option is D4x2−9y2=36 Equation of tangent to the hyperbola x2a2−y2b2=1 with slope m is given by y=mx±√a2m2−b2
Comparing it with y=mx±√9m2−4, we have a2=9 and b2=4 ∴ Equation of the hyperbola is x29−y24=1 ⇒4x2−9y2=36