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Question

For all real permissible values of m, if the straight lines y=mx±9m24 are tangents to a hyperbola, then equation of the hyperbola is

A
9x24y2=64
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B
4x29y2=64
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C
9x24y2=36
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D
4x29y2=36
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Solution

The correct option is D 4x29y2=36
Equation of tangent to the hyperbola x2a2y2b2=1 with slope m is given by
y=mx±a2m2b2
Comparing it with y=mx±9m24, we have
a2=9 and b2=4
Equation of the hyperbola is
x29y24=1
4x29y2=36

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