For all real values of x, the maximum value of the expression xx2−5x+9 is
A
1
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B
45
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C
90
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D
None of these
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Solution
The correct option is A1 y=xx2−5x+9 ⇒yx2−(5y+1)x+9y=0 As x is real, discriminant ≥0 ⇒(5y+1)2−36y2≥0 ⇒11y2−10y−1≤0 ∴y∈[−111,1] i.e. Maximum value of expression is 1. Hence, option A.