For all the sets A, B and C,
(A – B) ∩ (C – B) =

(A \cap C) \cap B'

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(A \cap C) - B

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(A \cap C) \cap B

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(A - C) - B

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Solution

The correct option is B $(A \cap C) - B$
$(A - B) \cap (C - B) = (A \cap B') \cap (C \cap B')$
[using distributive law of sets-
P ∪ (Q ∩ R) = (P ∪ Q) ∩ (P ∪ Q)]
$= (A \cap C) \cap B' = (A \cap C) - B$

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