For all x-12- simplify 6x2-x-24x2-1-

The correct option is E 3x 22x 1 The value of 6x^2 x 24x^2 1 , for x≠±12 is =6x^2 4x+3x 2(2x)^2 1^2 =2x(3x 2)+1(3x 2)(2x 1)(2x+1) ...

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Proportion

For all x±1...

Question

For all $x \neq \pm \frac{1}{2}$ , simplify $\frac{6 x^{2} - x - 2}{4 x^{2} - 1}$ .

\frac{2 - 3 x}{2 x + 1}

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\frac{3 x + 2}{2 x + 1}

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\frac{3 x + 2}{2 x - 1}

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\frac{3 x - 2}{2 x + 1}

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\frac{3 x - 2}{2 x - 1}

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∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 2 x^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣

3 x [x^{2} + 1] - [2 x (x^{2} + x - 1) + 1] - x^{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 {2 x}^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x - 12,

a^{2}

∣ ∣ ∣ ∣ ∣ \begin{matrix} x^{2} + x & x + 1 & x - 2 2 x^{2} + 3 x - 1 & 3 x & 3 x - 3 x^{2} + 2 x + 3 & 2 x - 1 & 2 x - 1 \end{matrix} ∣ ∣ ∣ ∣ ∣ = a x - 12

a

x

\frac{1}{2 (2 x + 3 x)} + \frac{12}{7 (3 x - 2 x)} = \frac{1}{2}

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