For an A.P. $a = 7, d = 3, n = 8$ , find $a_{8}$ .

a_{8} = 18

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a_{8} = 28

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a_{8} = 16

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a_{8} = 36

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Solution

The correct option is B $a_{8} = 28$
Here, $a = 7, d = 3$ and $n = 8$ .
By using $a_{n} = a + (n - 1) d$
Therefore, $a_{8} = a + 7 d$
$= 7 + 7 \times 3$
$= 28$

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