For an A.P. if t4=12 and d=−10, then its general term is
A
−10n+57
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B
−10n+52
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C
−10n+53
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D
−10n+51
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Solution
The correct option is A−10n+52 Let a be the first term and d be the common difference of given AP. Hence given that t4=12 and d=−10. ⇒a+3d=12 ⇒a+3×−10=12 ⇒a=12+30=42 general term of an AP is: tn=a+(n−1)d ⇒tn=42+(n−1)×−10 ⇒tn=−10n+52