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Question

For an A.P. if t4=12 and d=10, then its general term is

A
10n+57
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B
10n+52
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C
10n+53
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D
10n+51
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Solution

The correct option is A 10n+52
Let a be the first term and d be the common difference of given AP.
Hence given that t4=12 and d=10.
a+3d=12
a+3×10=12
a=12+30=42
general term of an AP is: tn=a+(n1)d
tn=42+(n1)×10
tn=10n+52

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