For an A.P., $t_{3} = 8$ and $t_{4} = 12$ . Find the common difference $d$ .

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Solution

Given, $t_{3} = 8, t_{4} = 12$
We know that, the common difference of an A.P. is the difference between any two consecutive terms.
The given terms $t_{3}$ and $t_{4}$ are consecutive.
$∴ d = t_{4} - t_{3}$
$\Rightarrow d = 12 - 8$
$\Rightarrow d = 4$

Hence, the common difference is $4$ .

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