Question

For an acute angle $\theta$ in a right angled triangle, $\tan \theta =$

• A. $\frac{1}{\cot \theta }$
• B. $\frac{1}{\sec \theta }$
• C. $\frac{1}{\text{cosec}\theta }$
• D. None of these

Answer 1

The correct option is A $\frac{1}{\cot \theta }$

$\tan \theta =\frac{\text{perpendicular}}{\text{base}}$ and

$\frac{1}{\cot \theta }=\frac{1}{\frac{\text{base}}{\text{perpendicular}}}=\frac{\text{perpendicular}}{\text{base}}$.

Hence, $\tan \theta =\frac{1}{\cot \theta }$.