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Byju's Answer
Standard XII
Physics
Thermodynamic Processes
For an adiaba...
Question
For an adiabatic expansion of perfect gas, the value of
(
Δ
P
P
)
is equal to
A
−
y
1
/
2
(
Δ
V
V
)
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B
−
(
Δ
V
V
)
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C
−
γ
(
Δ
V
V
)
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D
γ
2
(
Δ
V
V
)
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Solution
The correct option is
D
−
γ
(
Δ
V
V
)
In an adiabatic expansion of gas,
P
V
γ
=
c
o
n
s
t
a
n
t
Taking logarithm on both sides
l
n
(
P
)
+
γ
l
n
(
V
)
=
l
n
(
C
)
On differentiating:
Δ
P
P
+
γ
Δ
V
V
=
0
⇒
Δ
P
P
=
−
γ
Δ
V
V
Hence, option C is correct.
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