Question

For an AM wave, the maximum voltage was found to be $10V$ and minimum voltage was $4V$. The modulation index of the wave is

• A. $0.33$
• B. $0.43$
• C. $0.56$
• D. $0.64$

Answer 1

Answer: (B)

$0.43$

$m_a=\frac{V_{max}-V_{min}}{V_{max}+V_{min}}=\frac{10-4}{10+4}=\frac{6}{14}=0.43$