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Question

For an aqueous solution, freezing point is 0.1860C . Elevation of the boiling point is the same solution is : (Kf=1.860mol1kg and Kb=0.5120mol1kg)

A
0.1860C
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B
0.05120C
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C
1.860C
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D
5.120C
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Solution

The correct option is B 0.05120C
The depression in freezing point is given as follow:
ΔTf=Kfm
m=ΔTfKf=0186186
m=01
Now, elevation of the boiling point can be calculated as follow:
ΔTb=Kbm
=0512×0.1
=005120C

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