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Question

For an aqueous solution, freezing point is 0.186oC. The boiling point of the same solution is:

[Kf=1.86oCmol−1kg and Kb=0.512oCmol−1kg]

A
0.186 oC
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B
100.0512 oC
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C
1.86 oC
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D
5.12 oC
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Solution

The correct option is C 100.0512 oC
The freezing point of pure water is 0 deg C and that of the aqueous solution is 0.186 0C.

The depression in the freezing point ΔTf=0.1860=0.186 oC

ΔTf=Kf×m

0.186 oC=1.86 oCm×m

m=0.1 m

The aqueous solution is 1 molal.

The elevation in the boiling point
ΔTb=Kb×m

ΔTb=0.512 oCm×0.1 m

ΔTb=0.0512 oC

The boiling point of pure water is 100 deg C. The boiling point of the aqueous solution is 100+0.512=100.0512 oC

Hence, the correct option is B

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