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Question

For an electron placed in the second orbit of the hydrogen atom, calculate the number of revolutions per second made by it around the nucleus.

A
1.23×1013
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B
4.2×1012
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C
8.22×1014
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D
2.4×1015
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Solution

The correct option is C 8.22×1014
We know, radius of nth orbit r = 0.529×108n2 cm
radius of 2nd orbit =22×0.529×108 cm=2.12×108 cm
Also,
mvr=nh2π

v=nh2πmr

v=2×6.626×10272×3.14×(9.1×1028)×(2.12×108)

=1.09×108 cm/sec

Number of revolutions per second =v2πr=1.09×1082×3.14×2.12×108

=8.22×1014

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