Question

For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be:

• A. 0
• B. $\sqrt{6}\frac{h}{2\pi }$
• C. $\sqrt{2}\frac{h}{2\pi }$
• D. $3\left(\frac{h}{2\pi }\right)$

Answer 1

The correct option is C

$\sqrt{2}\frac{h}{2\pi }$

Radial node = (n - l - 1)

1=(3-l-1)

l=1

orbital angular momentum $=\sqrt{l(l+1)}\frac{h}{2\pi }$

$=\sqrt{1(1+1)}\frac{h}{2\pi }=\sqrt{2}\frac{h}{2\pi }$