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Question

For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be:


  1. 6h2π

  2. 2h2π

  3. 3(h2π)

  4. 0


Solution

The correct option is B

2h2π


Radial node = (n - l - 1)

1=(3-l-1)

l=1

orbital angular momentum =l(l+1)h2π

=1(1+1)h2π=2h2π

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