Question

# For an electron, with n = 3 has only one radial node. The orbital angular momentum of the electron will be: √6h2π √2h2π 3(h2π) 0

Solution

## The correct option is B √2h2π Radial node = (n - l - 1) 1=(3-l-1) l=1 orbital angular momentum =√l(l+1)h2π =√1(1+1)h2π=√2h2π

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