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Byju's Answer
Standard XII
Physics
Deducing Mathematically
For an engine...
Question
For an engine operating between the temperature
t
o
1
C
and
t
o
2
C
, the efficiency will be
A
t
1
−
t
2
t
1
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B
t
1
−
t
2
t
1
+
273
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C
t
2
+
273
t
1
+
273
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D
t
2
t
1
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Solution
The correct option is
D
t
1
−
t
2
t
1
+
273
The efficiency of the cycle
η
=
1
−
T
2
T
1
T
2
=
t
2
+ 273
T
1
=
t
1
+ 273
∴
1 -
T
2
T
1
= 1 -
t
2
+
273
t
1
+
273
=
t
1
−
t
2
t
1
+
273
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