MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Difference between Internal Energy and Enthalpy

For an ideal ...

Question

For an ideal gas Joule-Thomson coefficient is:

Open in App

Solution

As we know,
For an ideal gas, U(intermolecular) is equal to zero, because of absence of intermolecular force of attraction in ideal gas.
Hence, no heat is lost in the expansion and its Joule-Thomson coefficient is zero.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion :The Joule-Thomson coefficient for an ideal gas is zero. Reason: There are no intermolecular attractive forces in an ideal gas.

Q. Joule-Thomson coefficient is zero at:

The gas that does not show Joule Thomson effect is

Q. Match the List-I with List-II:

List-I	List-II
(I) Mixing of two ideal gases	1. $Δ G_{m i x} = 0$
(II) Criterion for irrevesibility	2. 1/ P
(III) Isobaric thermal coefficient of an ideal gas	3. 1/ T
(IV) Joule-Thomson effect	4. $Δ S_{T o t a l}^{o} > 0$ 5. $Δ G_{m i x} < 0$ 6. $Δ H = 0$

Q. Assertion :The gas on subjecting to Joule-Thomson effect gets heated if its temperature is less than its inversion temperature. Reason: Heating effect has Joule-Thomson coefficient -ve.

Read the above assertion and reason and choose the correct option regarding it.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Enthalpy

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Difference between Internal Energy and Enthalpy

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon