For an ideal gas the fractional change in its volume per degree rise in temperature at constant pressure is equal to [T is the absolute temperature of gas ]
A
T2
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B
T1
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C
T−1
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D
T−2
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Solution
The correct option is CT−1 From the ideal gas equation, PV=nRT .............(1) Differentiating w.r.tT on both sides, ⇒PdVdT=nR .............(2) [P,n and R are constant ] On dividing (2) by (1), ⇒PdVdTPV=nRnRT ⇒dVVdT=1T=T−1 Hence, fractional change in volume per unit rise in temperature is T−1.