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Thermodynamic Processes

For an ideal ...

Question

For an ideal gas with initial pressure and volume $P_{i}$ and $V_{i}$ respectively, a reversible isothermal expansion happens, when its volume becomes $V_{0}$ . Then it is compressed to its original volume $V_{i}$ by a reversible adiabatic process. If the final pressure is $P_{t}$ then which of the following statements is true?

P_{f} = P_{i}

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P_{f} > P_{i}

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P_{f} < P_{i}

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\frac{P_{f}}{V_{o}} = \frac{P_{i}}{V_{i}}

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Solution

The correct option is B $P_{f} > P_{i}$
It is clear from the image that $P_{f} > P_{i}$ .

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Similar questions

V_{i}

V_{f}

P_{i}

P_{f}

(P_{i}, V_{i})

(P_{f}, V_{f})

P_{f}

A B V_{f} V_{i}

(P_{i}, V_{i})

(P_{f}, V_{f})

C B V_{f} V_{i}

P_{f}

(P_{i}, V_{i})

(P_{f}, V_{f})

P_{f}

A B V_{f} V_{i}

(P_{i}, V_{i})

(P_{f}, V_{f})

C B V_{f} V_{i}

P_{f}

p_{i}

\frac{V}{n}

p_{a}

p_{i} / p_{a}

(γ = \frac{C_{p}}{C_{V}})

P_{i} = 10^{5}

V_{i} = 10^{- 3} m^{3}

P_{f} = (1 / 32) \times 10^{5}

V_{f} = 8 \times 10^{- 3} m^{3}

P^{3} V^{5} =

P_{i}

V_{f}

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