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Question

For an increasing A.P. a1,a2,a3...an,
if a1+a3+a5=12 and a1a3a5=80, then which of the following is true.


A

a1=+2

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B

a2=1

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C

a3=4

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D

a5=+2

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Solution

The correct option is D

a5=+2


a1+a3+a5=12

a+a+2d+a+4d=12

a+2d=4

a1a3a5=80

a(a+2d)(a+4d)=80

(a)(4)(a+4d)=80

a(a+4d)=20

(42d)(4+2d)=20

4d216=20

d=±3d=+3

Hence a=10

So, a5=2


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