Question

For an $LCR$ circuit, resonance frequency is ${\omega }_o$ and bandwidth is $△\omega$, then

• A. circuit is inductive for $({\omega }_o-\frac{△\omega }{2})$
• B. circuit is capacitive for $({\omega }_o+\frac{△\omega }{2})$
• C. circuit is resistive for $({\omega }_o-\frac{△\omega }{2})$
• D. circuit is inductive for $({\omega }_o+\frac{△\omega }{2})$

Answer 1

The correct option is D circuit is inductive for $({\omega }_o+\frac{△\omega }{2})$

At resonance frequency, the reactance of inductor and capacitor cancels out each other. Above the resonance frequency, the reactance of the inductor dominates, and below the resonance frequency, the reactance of the capacitor dominates.