For an octahedral complex M X 4 Y 2 M - a transition metal- X and Y are monodentate achrial ligands- the correct statement- among the following is-A- MX 4 Y 2 has 2 geometrical isomers one of which is chiralB- M X 4 Y 2 has 2 geometrical isomers both of which are achiralC- M X 4 Y 2 has 4 geometrical isomers all of which are achiralD- MX 4 Y 2 has 4 geometrical isomers two of which are chiral

The correct option is B MX_4Y_2 has 2 geometrical isomers both of which are achiral nbsp;Complex of the type MX_4Y_2 has only 2 geometrical isomers, both of ...

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Byju's Answer

Standard XII

Chemistry

Geometrical Isomerism in Square Planar Geometry

For an octahe...

Question

For an octahedral complex $M X_{4} Y_{2}$ (M = a transition metal , X and Y are monodentate achrial ligands), the correct statement, among the following is:

M X_{4} Y_{2}

has 2 geometrical isomers one of which is chiral

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M X_{4} Y_{2}

has 2 geometrical isomers both of which are achiral

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M X_{4} Y_{2}

has 4 geometrical isomers all of which are achiral

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M X_{4} Y_{2}

has 4 geometrical isomers two of which are chiral

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Solution

The correct option is B $M X_{4} Y_{2}$ has 2 geometrical isomers both of which are achiral
Complex of the type $M X_{4} Y_{2}$ has only 2 geometrical isomers, both of which are achiral.

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For an octahedral complex MX4Y2 (M = a transition metal , X and Y are monodentate achrial ligands), the correct statement, among the following is:

The correct option is B MX4Y2 has 2 geometrical isomers both of which are achiral Complex of the type MX4Y2 has only 2 geometrical isomers, both of which are achiral.

For an octahedral complex $M X_{4} Y_{2}$ (M = a transition metal , X and Y are monodentate achrial ligands), the correct statement, among the following is:

The correct option is B $M X_{4} Y_{2}$ has 2 geometrical isomers both of which are achiral
Complex of the type $M X_{4} Y_{2}$ has only 2 geometrical isomers, both of which are achiral.