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Byju's Answer
Standard XII
Physics
Maximum Range
For angles of...
Question
For angles of projection of a projectile at angles
(
45
∘
−
q
)
and
(
45
∘
+
q
)
the horizontal ranges described by the projectile are in the ratio of :-
A
1 :1
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B
2 :3
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C
1 :2
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D
2 :1
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Solution
The correct option is
A
1 :1
R
1
R
2
=
[
u
2
sin
2
(
45
−
θ
)
]
g
[
u
2
sin
2
(
45
+
θ
)
]
g
=
u
2
sin
(
90
−
2
θ
)
u
2
sin
(
90
+
2
θ
)
=
cos
2
θ
cos
θ
=
1
Hence,
option
(
A
)
is correct answer.
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1
Similar questions
Q.
For angles of projection of a projectile at angles
(
45
∘
−
θ
)
and
(
45
∘
+
θ
)
, the horizontal ranges described by the projectile are in the ratio of:
Q.
Galileo writes that for angles of projection of a projectile at angle
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Q.
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)
∘
and
(
45
−
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