Question

For any angle of measure $\theta$ prove that ${\sin }^2\theta +{\cos }^2\theta =1$.

Answer 1

$\begin{array}{c}\sin \theta =\frac{perpendicular}{hypo}=\frac{P}{H}\\ \cos \theta =\frac{base}{hypo}=\frac{B}{H}\\ \therefore paythaguras\\ H^2=P^2+B^2\\ \frac{H^2=P^2+B^2}{H^2}\\ \frac{H^2}{H^2}=\frac{p^2}{H^2}+\frac{B^2}{H^2}\\ 1={\sin }^{2}A+{\cos }^{2}A\end{array}$