GIven for any angle x^∘, we have the relation x^∘180^∘=x^cπ^c ⇒ x^c=x^∘180^∘×π^c ...

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Standard XII

Mathematics

Sexagesimal System

For any angle...

Question

For any angle $x^{\circ}, x^{c} =$

\frac{x °}{π^{c}} \times 180 °

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\frac{x °}{180 °} \times π^{c}

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x ° \times π^{c}

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Solution

The correct option is B $\frac{x °}{180 °} \times π^{c}$
GIven for any angle $x^{\circ},$ we have the relation $\frac{x^{\circ}}{180^{\circ}} = \frac{x^{c}}{π^{c}}$
$\Rightarrow x^{c} = \frac{x^{\circ}}{180^{\circ}} \times π^{c}$

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For any angle x∘,xc=

The correct option is B x°180°×πcGIven for any angle x∘, we have the relation x∘180∘=xcπc ⇒xc=x∘180∘×πc

For any angle $x^{\circ}, x^{c} =$

The correct option is B $\frac{x °}{180 °} \times π^{c}$
GIven for any angle $x^{\circ},$ we have the relation $\frac{x^{\circ}}{180^{\circ}} = \frac{x^{c}}{π^{c}}$
$\Rightarrow x^{c} = \frac{x^{\circ}}{180^{\circ}} \times π^{c}$