For any angle x- 0- 3- cosec x- 1 for

Given: cosec x ∀ x∈ (0, 3π) Now, to find the region where cosec x≥ 1 Let's plot the graph of cosec x: Thus, for x∈ (0, 3π), cosec x≥ 1 for x∈ (0, π)∪(2π, 3π) ...

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Byju's Answer

Standard XIII

Mathematics

Graph of Cosecant Function and it's Properties

For any angle...

Question

For any angle $x \in (0, 3 π), cosec x \geq 1$ for

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Solution

Given: $cosec x \forall x \in (0, 3 π)$
Now, to find the region where $cosec x \geq 1$
Let's plot the graph of $cosec x :$

Thus, for $x \in (0, 3 π), cosec x \geq 1$ for
$x \in (0, π) \cup (2 π, 3 π)$

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For any angle x∈(0,3π),cosec x≥1 for

Given: cosec x ∀ x∈(0,3π) Now, to find the region where cosec x≥1 Let's plot the graph of cosec x: Thus, for x∈(0,3π),cosec x≥1 for x∈(0,π)∪(2π,3π)

For any angle $x \in (0, 3 π), cosec x \geq 1$ for

Given: $cosec x \forall x \in (0, 3 π)$
Now, to find the region where $cosec x \geq 1$
Let's plot the graph of $cosec x :$

Thus, for $x \in (0, 3 π), cosec x \geq 1$ for
$x \in (0, π) \cup (2 π, 3 π)$