For any angle x- 0- - 2-cosec x-1-2-3- for x-

Given: x∈ (0, π)∪ (π, 2π) And we want to find the interval(s) for which cosec x∈[1,2√(3)]. Using the graph of cosec x: Thus, for cosex x∈[1,2√(3)] x∈[π3, 2π ...

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Byju's Answer

Standard XII

Mathematics

General Solutions of (sin theta)^2 = (sin alpha)^2 , (cos theta)^2 = (cos alpha)^2 , (tan theta)^2 = (tan alpha)^2

For any angle...

Question

For any angle $x \in (0, π) \cup (π, 2 π),$

$cosec x \in [1, \frac{2}{\sqrt{3}}] for x \in$

(\frac{π}{4}, \frac{3 π}{4}]

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(\frac{π}{6}, \frac{2 π}{3}]

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(\frac{π}{3}, \frac{2 π}{3}]

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Solution

The correct option is C $(\frac{π}{3}, \frac{2 π}{3}]$
Given: $x \in (0, π) \cup (π, 2 π)$
And we want to find the interval(s) for which $cosec x \in [1, \frac{2}{\sqrt{3}}] .$

Using the graph of $cosec x :$

Thus, for $cosex x \in [1, \frac{2}{\sqrt{3}}]$

$x \in [\frac{π}{3}, \frac{2 π}{3}]$

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For any angle x∈(0,π)∪(π,2π), cosec x∈[1,2√3] for x∈

The correct option is C (π3,2π3]Given: x∈(0,π)∪(π,2π) And we want to find the interval(s) for which cosec x∈[1,2√3]. Using the graph of cosec x: Thus, for cosex x∈[1,2√3] x∈[π3,2π3]

For any angle $x \in (0, π) \cup (π, 2 π),$

$cosec x \in [1, \frac{2}{\sqrt{3}}] for x \in$