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Byju's Answer
Standard XII
Mathematics
Area of Triangle with Coordinates of Vertices Given
For any angle...
Question
For any angle
x
,
cosec
x
−
cot
x
=
1
(
cosec
x
+
cot
x
)
.
A
False
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B
True
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Solution
The correct option is
B
True
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0
Similar questions
Q.
If
sec
x
=
√
2
and
3
π
2
<
x
<
2
π
, find the value of
1
+
tan
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+
c
o
s
e
c
x
1
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cot
x
−
c
o
s
e
c
x
Q.
If
|
cot
x
+
cosec
x
|
=
|
cot
x
|
+
|
cosec
x
|
;
x
∈
[
0
,
2
π
]
, then complete set of values of
x
is
Q.
Solve
c
o
s
e
c
x
=
1
+
cot
x
.
Q.
[
cos
e
c
x
−
sin
x
]
[
sec
x
−
cos
x
]
[
tan
x
+
cot
x
]
=
1
Q.
∫
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Area of Triangle with Coordinates of Vertices Given
Standard XII Mathematics
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